雲教課課程表

㈠ excel中如何自動提取教師個人課程表

1、先了解主課程表的內容，第一行主目錄，第二行是日期，第一列是時間，接下來是明細內容，整個excel分兩個sheet，第一頁是主課程表，第二頁是個人課程表。

㈡ Student 學生表 ，Course 課程表 ，SC成績表 ，Teacher 教師表，sql操作運用

建表語句

CREATE TABLE student
(
s# INT,
sname nvarchar(32),
sage INT,
ssex nvarchar(8)
)

CREATE TABLE course
(
c# INT,
cname nvarchar(32),
t# INT
)

CREATE TABLE sc
(
s# INT,
c# INT,
score INT
)

CREATE TABLE teacher
(
t# INT,
tname nvarchar(16)
)

插入測試數據語句

insert into Student select 1,N'劉一',18,N'男' union all
select 2,N'錢二',19,N'女' union all
select 3,N'張三',17,N'男' union all
select 4,N'李四',18,N'女' union all
select 5,N'王五',17,N'男' union all
select 6,N'趙六',19,N'女'

insert into Teacher select 1,N'葉平' union all
select 2,N'賀高' union all
select 3,N'楊艷' union all
select 4,N'周磊'

insert into Course select 1,N'語文',1 union all
select 2,N'數學',2 union all
select 3,N'英語',3 union all
select 4,N'物理',4

insert into SC
select 1,1,56 union all
select 1,2,78 union all
select 1,3,67 union all
select 1,4,58 union all
select 2,1,79 union all
select 2,2,81 union all
select 2,3,92 union all
select 2,4,68 union all
select 3,1,91 union all
select 3,2,47 union all
select 3,3,88 union all
select 3,4,56 union all
select 4,2,88 union all
select 4,3,90 union all
select 4,4,93 union all
select 5,1,46 union all
select 5,3,78 union all
select 5,4,53 union all
select 6,1,35 union all
select 6,2,68 union all
select 6,4,71

問題

問題： 1、查詢「001」課程比「002」課程成績高的所有學生的學號； select a.S# from (select s#,score from SC where C#='001') a,(select s#,score from SC where C#='002') b where a.score>b.score and a.s#=b.s#; 2、查詢平均成績大於60分的同學的學號和平均成績； select S#,avg(score) from sc group by S# having avg(score) >60; 3、查詢所有同學的學號、姓名、選課數、總成績； select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname 4、查詢姓「李」的老師的個數； select count(distinct(Tname)) from Teacher where Tname like '李%'; 5、查詢沒學過「葉平」老師課的同學的學號、姓名； select Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平'); 6、查詢學過「001」並且也學過編號「002」課程的同學的學號、姓名； select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002'); 7、查詢學過「葉平」老師所教的所有課的同學的學號、姓名； select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平')); 8、查詢課程編號「002」的成績比課程編號「001」課程低的所有同學的學號、姓名； Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2 from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score; 9、查詢所有課程成績小於60分的同學的學號、姓名； select S#,Sname from Student where S# not in (select S.S# from Student AS S,SC where S.S#=SC.S# and score>60); 10、查詢沒有學全所有課的同學的學號、姓名； select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course); 11、查詢至少有一門課與學號為「1001」的同學所學相同的同學的學號和姓名； select distinct S#,Sname from Student,SC where Student.S#=SC.S# and SC.C# in (select C# from SC where S#='1001'); 12、查詢至少學過學號為「001」同學所有一門課的其他同學學號和姓名； select distinct SC.S#,Sname from Student,SC where Student.S#=SC.S# and C# in (select C# from SC where S#='001'); 13、把「SC」表中「葉平」老師教的課的成績都更改為此課程的平均成績； update SC set score=(select avg(SC_2.score) from SC SC_2 where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平'); 14、查詢和「1002」號的同學學習的課程完全相同的其他同學學號和姓名； select S# from SC where C# in (select C# from SC where S#='1002') group by S# having count(*)=(select count(*) from SC where S#='1002'); 15、刪除學習「葉平」老師課的SC表記錄； Delect SC from course ,Teacher where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平'; 16、向SC表中插入一些記錄，這些記錄要求符合以下條件：沒有上過編號「003」課程的同學學號、2、 號課的平均成績； Insert SC select S#,'002',(Select avg(score) from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002'); 17、按平均成績從高到低顯示所有學生的「資料庫」、「企業管理」、「英語」三門的課程成績，按如下形式顯示： 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分 SELECT S# as 學生ID ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語 ,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績 FROM SC AS t GROUP BY S# ORDER BY avg(t.score) 18、查詢各科成績最高和最低的分：以如下形式顯示：課程ID，最高分，最低分 SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分 FROM SC L ,SC AS R WHERE L.C# = R.C# and L.score = (SELECT MAX(IL.score) FROM SC AS IL,Student AS IM WHERE L.C# = IL.C# and IM.S#=IL.S# GROUP BY IL.C#) AND R.Score = (SELECT MIN(IR.score) FROM SC AS IR WHERE R.C# = IR.C# GROUP BY IR.C# );
自己寫的:select c# ,max(score)as 最高分 ,min(score) as 最低分 from dbo.sc group by c# 19、按各科平均成績從低到高和及格率的百分數從高到低順序 SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績 ,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數 FROM SC T,Course where t.C#=course.C# GROUP BY t.C# ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC 20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理（001），馬克思（002），OO&UML （003），資料庫（004） SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分 ,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數 ,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分 ,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數 ,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分 ,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數 ,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分 ,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數 FROM SC

21、查詢不同老師所教不同課程平均分從高到低顯示
SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查詢如下課程成績第 3 名到第 6 名的學生成績單：企業管理（001），馬克思（002），UML （003），資料庫（004）
[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績
SELECT DISTINCT top 3
SC.S# As 學生學號,
Student.Sname AS 學生姓名 ,
T1.score AS 企業管理,
T2.score AS 馬克思,
T3.score AS UML,
T4.score AS 資料庫,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 課程ID, Cname as 課程名稱
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;

24、查詢學生平均成績及其名次
SELECT 1+(SELECT COUNT( distinct 平均成績)
FROM (SELECT S#,AVG(score) AS 平均成績
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成績 > T2.平均成績) as 名次,
S# as 學生學號,平均成績
FROM (SELECT S#,AVG(score) 平均成績
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成績 desc;

原文地址：http://www.cnblogs.com/qixuejia/p/3637735.html

㈢ 教師課程安排中安排好各班各科教師，總課表中各班各科安排好後，科目下面顯示安排表中安排好的教師姓名

這個屬於Excel吧，應該在Excel裡面建立吧，很簡單的，先打一個表格嘛，把你每科的老師的名字寫下來嘛，再把這個課程表寫下來就行了呀，你很聰明

㈣ 資料庫建表，一個老師帶一門課卻可以有幾個班，那麼學生選課表和教師授課表應該怎麼建

這么設計
教師-課程-班級表 存教師id、課程id和班級id
班級-學生表 存班級id和學生id
應該能滿足你的需求了吧

㈤ 教你使用超級課程表如何蹭課的方法教程

超級課程表怎麼蹭課？今天小編將演示超級課程表蹭課教程，超級課程表是專門為大學生朋友開發的軟體，蹭課功能很實用哦。還不了解具體使用方法的朋友請看下文。 相關教程：超級課程表怎麼導入課程 1）首先打開超級課程表，打&ldq... 展開全部》