多进程程序设计课程设计

Ⅰ 操作系统课程设计编程模拟多进程共享临界资源

我在上学时没学好，也是和你一样，在网上求助。只是结果不怎么样。还是好好学习，天天向上吧。

Ⅱ 急！！！！！！汇编程序设计课程设计

data segment
year db "year:",0ah,0dh,"$"
month db "month:",0ah,0dh,"$"
day db "day:",0ah,0dh,"$"
hour db "hour:",0ah,0dh,"$"
minute db "minute:",0ah,0dh,"$"
second db "second:",0ah,0dh,"$"
shuchu macro
mov bl,al
mov ah,al
mov cl,4
shr ah,cl
and al,0fh
add ax,3030h
push ax
mov dl,ah
mov ah,2
int 21h
pop ax
mov ah,2
mov dl,al
int 21h
endm
rcmos macro jk
mov al,jk
out 70h,al
in al,71h
cmp al,bl ;秒输出时,是否相同
endm
ymdhm macro dz,jk1
writes dz
rcmos jk1
shuchu
cr
endm
data ends
writes macro a
lea dx,a
mov ah,9
int 21h
endm
cr macro
push ax
push dx
mov dl,0ah
mov ah,2
int 21h
mov dl,0dh
mov ah,2
int 21h
pop dx
pop ax
endm
code segment
assume cs:code,ds:data
start: mov ax,data
mov ds,ax
ymdhm year,9
ymdhm month,8
ymdhm day,7
ymdhm hour,4
ymdhm minute,2
writes second
begin: rcmos 0
je begin ;若相同则返回
cmp al,0
jne next
push bx
push ax
ymdhm minute,2
writes second
pop ax
pop bx
next: shuchu
cr
mov ah,0bh
int 21h
cmp al,0
jnz done
jmp begin
done: mov ah,4ch
int 21h
code ends
end start

Ⅲ C语言程序设计 (学生选修课程设计)

这是我做的，你看是否满意？可能有点大，但也没办法呀，你的题目也比较大，呵呵！所以，如果满意，多给我追加点分！
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
typedef struct course
{
char number[15],name[25];
int kind,time,lessontime,practicetime,credit,term;
}type;
FILE *fp1;
void overview(); //浏览函数，负责浏览整个课程信息
void seek(); //查询函数，负责查询课程信息
void choose_course();//选课函数，负责让用户选课
void out(type temp);
void input();
int main()
{
int n,i;
if((fp1=fopen("course_information.txt","wb"))==NULL)
{printf("创建文件失败!\n");exit(0);}
printf("请输入要存储的课程数目:\n");
scanf("%d",&n);
printf("开始创建文件，请输入课程信息:\n\n");
for(i=0;i<n;i++)
{
printf("请输入第%d门课程的信息:\n",i+1);
input();
printf("\n");
}
printf("如想浏览整个课程信息，请输入1；如想查询课程信息，请输入2； 如想进行选课，请输入3；如想结束选修课系统，请输入0!\n");
while((scanf("%d",&n))!=EOF)
{
if(n==1)
overview();
if(n==2)
seek();
if(n==3)
choose_course();
if(n==0)
exit(0);
printf("\n\n如想继续操作，只要按规则输入你要进行的操作即可!\n规则:如想浏览整个课程信息，请输入1；如想查询课程信息，请输入2；如想进行选课，请输入3!\n");
}
printf("欢迎您使用此程序进行选课，谢谢!\n");
fclose(fp1);
return 0;
}
void input()
{
course c_a;
printf("请输入课程编码: ");
scanf("%s",c_a.number);
printf("请输入课程名: ");
scanf("%s",c_a.name);
printf("请输入课程性质：限选课，请输入1；选修课，请输入2；必修课，请输入3! ");
scanf("%d",&c_a.name);
printf("请输入课程总学时: ");
scanf("%d",&c_a.time);
printf("请输入课程授课时间: ");
scanf("%d",&c_a.lessontime);
printf("请输入课程实验或实践时间: ");
scanf("%d",&c_a.practicetime);
printf("请输入课程学分: ");
scanf("%d",&c_a.credit);
printf("请输入课程所在的学期，比如第二学期，就输入2即可。");
scanf("%d",&c_a.term);
fwrite(&c_a,sizeof(struct course),1,fp1);//将一个结构体元素写入文件中
}
void out(type temp)
{
printf("课程代码: %s\n课程名: %s\n",temp.number,temp.name);
printf("课程名: %s\n",temp.name);
if(temp.kind==1)
printf("课程性质: Limited optional course\n");
else if(temp.kind==2)
printf("课程性质: Optional course\n");
else if(temp.kind==3)
printf("课程性质: Required Courses\n");
else
printf("该编码系统不认识，即无对应的课程性质存在!\n");
printf("课程总学时: %d\n课程授课学时: %d\n实验或上机学时: %d\n学分: %d\n课程开课学期: %d\n\n",temp.time,temp.lessontime,temp.practicetime,temp.credit,temp.term);
}
void overview()
{
rewind(fp1);
course temp;
printf("整个课程信息如下:\n");
while((fread(&temp,sizeof(type),1,fp1))!=0)
out(temp);
}
void seek()
{
int judge,credit=0,kind=0;
char a='N';
course temp;
printf("如想按学分查询，请输入1；如想按课程性质，请输入2:\n");
scanf("%d",&judge);
rewind(fp1); //将文件指针位置置为开头
if(judge==1)
{
printf("请输入要查询的学分:\n");
scanf("%d",&credit);
while((fread(&temp,sizeof(type),1,fp1))!=0)
if(credit==temp.credit)
out(temp);
}
else if(judge==2)
{
printf("请输入你要查找课程的性质(限选课，请输入1；选修课，请输入2；必修课，请输入3):");
scanf("%d",&kind);
while((fread(&temp,sizeof(type),1,fp1))!=0)
if(temp.kind==kind)
out(temp);
}
else
printf("不好意思，无此类查询!\n");
}
void choose_course()
{
rewind(fp1);
course temp;
int judge=1,n=0,time=0,credit=0;
char choose[20][20];
r1: printf("请开始填写课程编号进行选课：\n");
while(judge==1)
{
printf("请输入你所选课程的标号： ");
scanf("%s",choose[n]);
n++;
printf("如想继续选课，请输入1；如想提交，请输入0!\n");
scanf("%d",&judge);
}
while((fread(&temp,sizeof(type),1,fp1))!=0)
{
for(int i=0;i<n;i++)
if(strcmp(temp.number,choose[i])==0)
{time=time+temp.time;credit=temp.credit;break;}
}
if(time<270||credit<40)
goto r1;
printf("你所选的课为：\n");
while((fread(&temp,sizeof(type),1,fp1))!=0)
{
for(int i=0;i<n;i++)
if(strcmp(temp.number,choose[i])==0)
{out(temp);break;}
}
}

Ⅳ C语言程序设计课程设计都需要做什么啊

我这有相似的程序，在我的作业里 给我个邮箱 我发过去

Ⅳ 《C语言程序设计》课程设计任务书 请各位高手指教啊！十万火急！！！！

#include <graphics.h>
#include <conio.h>
#include <dos.h>
#include <malloc.h>
#include <math.h>

#define PATH "c:\\tc"
#define BK 7
#define DC 8
#define LC 15
#define P1 1
#define P2 4
#define X 121
#define Y 41
#define M 8

int newmap[26][14] ={{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0, 1,1},
{1,1, 0,0,0,0,0,0,0,0,0,0 , 1,1},
{1,1, 1,1,1,1,1,1,1,1,1,1, 1,1},
{1,1, 1,1,1,1,1,1,1,1,1,1, 1,1}};

int bmp[20][20]={{0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0},
{0,1,1,1,1,0,1,1,1,1,1,1,1,1,0,1,1,1,1,0},
{1,1,1,0,0,0,1,1,0,0,0,0,1,1,0,0,0,1,1,1},
{1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1},
{1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1},
{1,0,0,0,0,1,1,1,0,1,1,0,1,1,1,0,0,0,0,1},
{1,1,1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,1,1},
{1,1,1,1,1,1,1,1,0,0,0,0,1,1,1,1,1,1,1,1},
{1,1,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,1,1},
{1,1,0,1,1,1,1,0,1,1,1,1,0,1,1,1,1,0,1,1},
{1,1,0,1,1,1,1,0,1,1,1,1,0,1,1,1,1,0,1,1},
{1,1,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,1,1},
{1,1,1,1,1,1,1,1,0,0,0,0,1,1,1,1,1,1,1,1},
{1,1,1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,1,1},
{1,0,0,0,0,1,1,1,0,1,1,0,1,1,1,0,0,0,0,1},
{1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1},
{1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1,0,1,1},
{1,1,1,0,0,0,1,1,0,0,0,0,1,1,0,0,0,1,1,1},
{0,1,1,1,1,0,1,1,1,1,1,1,1,1,0,1,1,1,1,0},
{0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0}};
int next;
int xx,yy;
int map[2][26][14];
int kk[M][4][4]= {
{
{0,0,0,0},
{0,0,2,0},
{0,2,2,2},
{0,0,0,0}
},

{
{0,0,0,0},
{0,2,0,0},
{0,2,0,0},
{0,2,2,0}
},

{
{0,2,0,0},
{0,2,0,0},
{0,2,0,0},
{0,2,0,0}
},

{
{0,0,2,0},
{0,0,2,0},
{0,2,2,0},
{0,0,0,0}
},

{
{0,0,0,0},
{0,2,0,0},
{0,2,2,0},
{0,0,2,0}
},

{
{0,0,0,0},
{0,2,2,0},
{0,2,2,0},
{0,0,0,0}
},

{
{0,0,0,0},
{0,2,2,0},
{0,0,2,0},
{0,2,2,0}
},
{
{0,0,0,0},
{0,0,2,0},
{0,2,2,0},
{0,2,0,0}
}
};

char far * bit[3],*sim;
int score,level;
/************/
int getkey();
void edge(int l,int t,int r,int b,int c1,int c2);
void init();
void new();
void newk();
void draw(int x,int y,int c);
void show();
void close();
void down();
int candown();
void tobotton();
int canturn();
void turn();
int canleft();
void left();
int canright();
void right();
int isok(int x);
void ok(int x);
void showscore();
void drawnext();
int isover();
void over();

int getkey()
{
char ch=0;
if(kbhit())
ch=getch();
return(ch);
}

void init()
{
int gdriver=DETECT,gmode;
int size,i,j;
/* registerbgidriver();*/
initgraph(&gdriver,&gmode,PATH);
setbkcolor(BK);
setfillstyle(11,8);
edge(X-9,Y-9,X+408,Y+408,DC,DC);
floodfill(1,1,DC);
edge(X-9,Y-9,X+408,Y+408,DC,LC);
edge(X-7,Y-7,X+406,Y+406,DC,LC);

edge(X-1,Y-1,X+201,Y+401,DC,LC);
edge(X-3,Y-3,X+203,Y+403,LC,DC);

edge(X+260,Y-1,X+341,Y+81,DC,LC);
edge(X+258,Y-3,X+343,Y+83,LC,DC);

size=imagesize(X+1,Y+1,X+20,Y+20);
bit[0]=(char far*)malloc(size);

if(bit[0]==NULL){sound(2000);getch();nosound();exit(1);}

getimage(X+1,Y+1,X+20,Y+20,bit[0]);

for(i=0;i<20;i++)
for(j=0;j<20;j++)
if(bmp[i][j]==1)
putpixel(X+1+j,Y+1+i,P1);
bit[1]=(char far*)malloc(size);

if(bit[1]==0){sound(2000);getch();nosound();exit(1);}

getimage(X+1,Y+1,X+20,Y+20,bit[1]);

for(i=0;i<20;i++)
for(j=0;j<20;j++)
if(bmp[i][j]==1)
putpixel(X+1+j,Y+1+i,P2);
bit[2]=(char far*)malloc(size);

getimage(X+1,Y+1,X+20,Y+20,bit[2]);

setcolor(8);
outtextxy(X+245,Y+95,"score");
outtextxy(X+320,Y+95,"level");
edge(X+240,Y+107,X+290,Y+122,LC,DC);
edge(X+242,Y+109,X+288,Y+120,DC,LC);
edge(X+315,Y+107,X+365,Y+122,LC,DC);
edge(X+317,Y+109,X+363,Y+120,DC,LC);

size=imagesize(X+240,Y+107,X+290,Y+122);
sim=(char far *)malloc(size);
getimage(X+240,Y+107,X+290,Y+122,sim);

edge(X+207,Y+133,X+400,Y+401,LC,DC);
edge(X+210,Y+135,X+397,Y+398,LC,DC);

outtextxy(X+213,Y+140,"Control Option:");
outtextxy(X+213,Y+150,"-----------------");
outtextxy(X+213,Y+160," [P]--Start/Pause");
outtextxy(X+213,Y+177," [Esc]--Quit the game");
outtextxy(X+213,Y+194," [W]--Turn");
outtextxy(X+213,Y+211," [A]--Left");
outtextxy(X+213,Y+228," [S]--Down fast");
outtextxy(X+213,Y+245," [D]--Right");
outtextxy(X+213,Y+262,"[Space]--Down to botton");

for(i=0;i<4;i++)
edge(X+213+i*3,Y+278+i*4,X+394-i*3,Y+391-i*4,DC,LC);
outtextxy(X+224,Y+300," This game was");
outtextxy(X+224,Y+312,"programed by jackin.");
outtextxy(X+224,Y+324," If you discover" );
outtextxy(X+224,Y+336,"errors in it ,please");
outtextxy(X+224,Y+348," email to:");
setcolor(4);
outtextxy(X+224,Y+360," [email protected]");

if(bit[0]==0||bit[1]==0||bit[2]==0||sim==0)
{
close();
exit(1);
}
putimage(X+1,Y+1,bit[0],0);
}

void edge(int l,int t,int r,int b,int c1,int c2)
{
int cl=getcolor();
setcolor(c1);
line(l,t,r-1,t);
line(l,t,l,b-1);
setcolor(c2);
line(r,t,r,b);
line(l,b,r,b);
setcolor(cl);
}

void draw(int x,int y,int c)
{
putimage(X+20*y,Y+x*20,bit[c],0);
}

void show()
{
int i,j;
for(i=0;i<20;i++)
for(j=0;j<10;j++)
if(map[1][i+4][j+2]!=map[0][i+4][j+2])
{
map[0][i+4][j+2]=map[1][i+4][j+2];
draw(i,j,map[1][i+4][j+2]);
}

}

void close()
{
int i;
for(i=0;i<3;i++)
free(bit[i]);
free(sim);
closegraph();
}

void new()
{
int i,j,t=-1;

score=0;
level=1;
showscore();

for(i=0;i<26;i++)
for(j=0;j<14;j++)
{
map[1][i][j]=newmap[i][j];
map[0][i][j]=0;
}

for(;t<0;)
t=rand();
next=t%M;
}

void newk()
{
int i,j,t=-1;
xx=1;
yy=5;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
map[1][xx+i][j+yy]=kk[next][i][j];

for(;t<0;)
t=rand();
next=t%M;
show();
}

int candown()
{
int i,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
{
if(map[1][xx+i][yy+j]==2&&map[1][xx+i+1][yy+j]==1)
return(0);
}
return(1);
}

void down()
{
int i,j;
xx++;
for(i=3;i>=0;i--)
for(j=3;j>=0;j--)
{
if(map[1][xx+i-1][yy+j]!=1)
{
if(map[1][xx+i][yy+j]!=1)
map[1][xx+i][yy+j]=map[1][xx+i-1][yy+j];
}
else
{
if(map[1][xx+i][yy+j]!=1)
map[1][xx+i][yy+j]=0;
}
}
for(j=0;j<4;j++)
if(map[1][xx-1][yy+j]==2)
map[1][xx-1][yy+j]=0;
}

void tobotton()
{
int i,j;
for(i=3;i>=0;i--)
for(j=3;j>=0;j--)
if(map[1][xx+i][yy+j]==2)
map[1][xx+i][yy+j]=1;
}

int canturn()
{
int i,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(map[1][xx+3-j][i+yy]==1&&map[1][xx+i][j+yy]==2)
return(0);
return(1);
}

void turn()
{
int i,j,t[4][4];
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(map[1][xx+i][j+yy]==1)
t[i][j]=0;
else
t[i][j]=map[1][xx+i][j+yy];
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(map[1][xx+i][j+yy]!=1)
map[1][xx+i][j+yy]=t[j][3-i];
}

int canleft()
{
int i,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
{
if(map[1][xx+i][yy+j]==2&&map[1][xx+i][yy+j-1]==1)
return(0);
}
return(1);
}

void left()
{
int i,j;
yy--;
for(i=3;i>=0;i--)
for(j=0;j<4;j++)
{
if(map[1][xx+i][yy+j+1]!=1)
{
if(map[1][xx+i][yy+j]!=1)
map[1][xx+i][yy+j]=map[1][xx+i][yy+j+1];
}
else
{
if(map[1][xx+i][yy+j]!=1)
map[1][xx+i][yy+j]=0;
}
}
for(j=0;j<4;j++)
if(map[1][xx+j][yy+4]==2)
map[1][xx+j][yy+4]=0;
}

int canright()
{
int i,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
{
if(map[1][xx+i][yy+j]==2&&map[1][xx+i][yy+j+1]==1)
return(0);
}
return(1);
}

void right()
{
int i,j;
yy++;
for(i=3;i>=0;i--)
for(j=3;j>=0;j--)
{
if(map[1][xx+i][yy+j-1]!=1)
{
if(map[1][xx+i][yy+j]!=1)
map[1][xx+i][yy+j]=map[1][xx+i][yy+j-1];
}
else
{
if(map[1][xx+i][yy+j]!=1)
map[1][xx+i][yy+j]=0;
}
}
for(j=0;j<4;j++)
if(map[1][xx+j][yy-1]==2)
map[1][xx+j][yy-1]=0;
}

int isok(int x)
{
int i;
if(x>23)return(0);
for(i=2;i<12;i++)
if(map[1][x][i]==0||map[1][x][i]==2)
return(0);

return(1);
}

void ok(int x)
{
int i;
for(;x>0;x--)
for(i=2;i<12;i++)
map[1][x][i]=map[1][x-1][i];
score++;
level=score/10+1;
}

void showscore()
{
char s[20],l[20];
itoa(score,s,10);
itoa(level,l,10);
putimage(X+240,Y+107,sim,0);
putimage(X+315,Y+107,sim,0);
outtextxy(X+244,Y+111,s);
outtextxy(X+325,Y+111,l);
}

void drawnext()
{
int x,y;
for(x=0;x<4;x++)
for(y=0;y<4;y++)
{
putimage(X+261+20*y,Y+x*20,bit[kk[next][x][y]],0);
}
}

int isover()
{
int i;
for(i=2;i<12;i++)
if(map[1][3][i]==1)return(1);
return(0);
}

void over()
{
int i,j;
for(i=23;i>3;i--)
{
for(j=2;j<12;j++)
map[1][i][j]=1;
show();
delay(1000);
}
for(i=4;i<24;i++)
{
for(j=2;j<12;j++)
map[1][i][j]=0;
show();
delay(1000);
}
}

main()
{ int graphdriver=DETECT;
int graphmode;
int i,j;
char cc;
init();
start:
cc=getkey();
for(;cc!='p'&&cc!='P';)
{
rand();
if(cc==27)goto end;
cc=getkey();
}
new();
newk();
for(;;)
{
for(i=0;i<20000-level*1000;i++)
{
switch(getkey())
{
case 27:
over();
goto end;
case 'w':
case 'W':
if(canturn())
turn();
break;
case 'a':
case 'A':
if(canleft())
left();
break;
case 's':
case 'S':
if(candown())
{
down();
}
else
{

}
break;
case 'd':
case 'D':
if(canright())
right();
break;
case ' ':
for(;candown();)
down();
break;
case 'p':
case 'P':
cc=getkey();
for(;cc!='p'&&cc!='P';)
{
if(cc==27)goto end;
cc=getkey();
}
break;
default:break;
}
show();
}
drawnext();
if(candown())
{
down();
show();
}
else
{
tobotton();
for(j=1;j<24;j++)
if(isok(j))
{
ok(j);
score++;
showscore();
}
if(isover())
{
over();
goto start;
}
newk();
show();
}
}
end:
close();
getch();
}

Ⅵ 操作系统课程设计作业 很急！题目是Windows平台上的多进程（线程）编程

你好，
这种问题是没有人会来帮助你的，网友们能帮你的只能是方法，如果你想不劳而获，那你就不用来这里浪费时间了。

Ⅶ C语言程序设计课程设计！

图书借阅管理，C语言编程的，只要设计部分的，，m

Ⅷ linux课程设计具有多进程处理的聊天程序设计

多线程程序设计的概念早在六十年代就被提出,但直到...2.2 Linux 下的进程控制 在传统的Unix 环境下,有...其实UNIX 自有其解决 的办法,

Ⅸ 《C语言程序设计》课程设计

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<conio.h>

#define BUFFERSIZE 1024
#define MAXACCOUNT 1000
typedef struct BankAccount
{
int account;
int key;
char name[32];
float balance;
}BANKACCOUNT;

BANKACCOUNT accountCollection[MAXACCOUNT];
int curAccount = 0;

void InsertAccount(FILE *fp)
{
BANKACCOUNT newaccount;
printf("please input the account information\n");
printf(">>account num:");
scanf("%d",&(newaccount.account));
printf(">>key:");
scanf("%d",&(newaccount.key));
printf(">>name:");
scanf("%s",newaccount.name);
printf(">>balance:");
scanf("%f",&(newaccount.balance));
fseek(fp,0L,SEEK_END);
fprintf(fp,"%d %d %s %.2f\n",newaccount.account,newaccount.key,newaccount.name,newaccount.balance);
}
void GetAccount(FILE *fp)
{
int accountnum;
int key;
char name[32];
float balance;
int i =0,j;
char buffer[BUFFERSIZE];
int len;
curAccount = 0;
fseek(fp,0,SEEK_SET);
while(!feof(fp)) /* 因为feof()最后会读2遍，所以最后curAccount多加了1 */
{
fscanf(fp,"%d %d %s %f",&accountnum,&key,name,&balance);
accountCollection[curAccount].account = accountnum;
accountCollection[curAccount].key = key;
strcpy(accountCollection[curAccount].name ,name);
accountCollection[curAccount].balance = balance;
curAccount++;
}
}
void ListAccount(FILE *fp)
{
int i =0;
printf("There is %d accounts at all:\n",curAccount-1);/* curAccount减去多加的1 */
for(i = 0;i< curAccount-1;i++)
{
printf("ACCOUNT[%d]:\n",i+1);
printf("account:%d\n",accountCollection[i].account);
printf("name:%s\n",accountCollection[i].name);
printf("balance:%.2f\n",accountCollection[i].balance);
}
}
int SearchAccount(FILE *fp,int accountnum)
{
int i =0;
for(i = 0;i< curAccount-1;i++)
{
if(accountCollection[i].account == accountnum)
{
printf("ACCOUNT[%d]:\n",i+1);
printf("account:%d\n",accountCollection[i].account);
printf("name:%s\n",accountCollection[i].name);
printf("balance:%.2f\n",accountCollection[i].balance);
return 1;
}
}
return 0;
}
void DelAccount(FILE *fp,int accountnum)
{
int i;
if(SearchAccount(fp,accountnum)==0)
printf("Can't find the account\n");
else
{
for(i = 0;i<curAccount-1;i++)
{
if(accountCollection[i].account != accountnum)
fprintf(fp,"%d %d %s %.2f\n",accountCollection[i].account,accountCollection[i].key,accountCollection[i].name,accountCollection[i].balance);
}
printf("delete successfully!\n");
}
}

int main()
{
FILE *fp;
int accountnum;
int i;
do{
system("cls"); //清屏
puts("********************************************");
puts("* You can choose : *");
puts("* 1 : Insert a new Account *");
puts("* 2 : List all Accounts *");
puts("* 3 : Find a Account *");
puts("* 4 : Delete a Account *");
puts("* 5 : quit *");
puts("********************************************");
printf("Please input your choice:");
scanf("%d",&i);
system("cls"); //清屏
switch(i)
{
case 1:
if(!(fp = fopen("account.txt","a+")))
{
printf("can't open the file account.txt\n");
exit(0);
}
InsertAccount( fp);

printf("press any key to continue.....\n");
getch();
fclose(fp);
break;
case 2:
if(!(fp = fopen("account.txt","r")))
{
printf("can't open the file account.txt\n");
exit(0);
}
GetAccount(fp);
ListAccount(fp);

fclose(fp);
printf("press any key to continue.....\n");
getch();
break;
case 3:
printf("please input the account num:\n");
scanf("%d",&accountnum);
if(!(fp = fopen("account.txt","r")))
{
printf("can't open the file account.txt\n");
exit(0);
}
GetAccount(fp);
if(!SearchAccount(fp,accountnum))
printf("There is not the account:%d\n",accountnum);

fclose(fp);
printf("press any key to continue.....\n");
getch();
break;
case 4:
printf("please input the account num:\n");
scanf("%d",&accountnum);
if(!(fp = fopen("account.txt","r")))
{
printf("can't open the file account.txt\n");
exit(0);
}
GetAccount(fp);
fclose(fp);
if(!(fp = fopen("account.txt","w+")))
{
printf("can't open the file account.txt\n");
exit(0);
}
DelAccount(fp,accountnum);
fclose(fp);
printf("press any key to continue.....\n");
getch();
break;
default:
break;
}
}while(i != 5);
return 0;
}
账户数据文件名已经设定为account.txt，这个文件要和上面这个程序放在同一个文件夹下面，不然就得用绝对路径(比如"d:\\book\\account.txt")，account内容可以用记事本打开自己改动，然后运行程序后就可以在程序中添加或删除

Ⅹ 求2个程序设计方法C++程序，课程设计用。

#include<iostream>
using namespace std;
int a[10];
int main()
{
void getdata();
void sort(int array[],int n);
getdata();
sort(a,10);
cout<<"降序排列的数组为：";
for(int i=0;i<10;i++)
cout<<a[i]<<" ";
cout<<endl;
return 0;
}
void getdata()
{
cout<<"请输入数据：";
for(int i=0;i<10;i++)
cin>>a[i];
}
void sort(int array[],int n)
{
int i,j,t;
for(j=0;j<9;j++)
for( i=0;i<9-j;i++)
if(array[i]<array[i+1])
{
t=array[i];
array[i]=array[i+1];
array[i+1]=t;
}
}

#include <iostream>
using namespace std;

int units[]={1,11,111,1111,11111,111111,1111111,11111111,111111111};

int main()
{
int a,n;
cout<<"Enter a:"<<endl;
cin>>a;
cout<<"Enter n:"<<endl;
cin>>n;
int s=units[n-1];
for(int i=n-2;i>=0;i--)
{
s-=units[i];
}
cout<<s*a<<endl;

}