丅S课程表

① SQL语句的一道题 三个基本表：学生表(Student)、课程表（Course）、学生选课表（SC）

1. select * from SC
2. select Sname，Sage from Student where Sdept = '计算机'
3. select Sno,Cno,Grade from SC where Grade >= 70 and Grade <= 80
4. select Sname,Sage from Student where Sage between 18 and 20 and Ssex = '男'
5. select top 1 Grade from SC where Cno = 'C01'
6. select max(Sage),min(Sage) from Student
7. select Sdept,sum(Sno) from Student group by Sdept
8. select course.Cname,sum(sc.Sno),max(Grade) from SC
join studet on Student.Sno = SC.Sno
join Course on Course.Cno = SC.Cno
group by course.cname,max(grade)

9. select sum(Cno),avg(Grade) from SC
join Course on Course.Cno = SC.Cno
join Student on Student.Sno= SC.Sno
order by SC.Sno

10. select Stuent.Sno，Stuent.Sname，sum(Grade) A from SC
join Student on Student.Sno = SC.Sno
group by sc.Sno,student.Sname
having A > 200

11. select Student.Sname,Student.Sdept from Student
join Course on Course.Cno = SC.Cno
join SC on SC.Sno = Student.Sno
where SC.Cno = 'C02'

12. select Student.sname,course.cno,sc.grade from sc
join student on student.sno = sc.sno
join course on course.cno = sc.cno
where sc.grade >= 80
order by sc.grade desc

13. select cno,cname from
(
select course.cno,course.cname,sun(sno) from student
join course on course.cno = sc.cno
join sc on sc.sno = student.sno
group by cno,cname
having sun(sno) > 0
)

14. ① select student.sname,student.sdept from
(
select student.sname,student.sdept,course.cname from student
join sc on sc.sno = student.sno
join course on course.cno = sc.cno
where course.cname = 'C01'
)

② select student.sno,student.sname from
(
select student.sno,student.sname,student.sdept,sc.grade from sc
join student on student.sno = sc,sno
where student.sdept = '信息' and sc.grade >= 80
)

③ select top 1 student.sname from
(
select student.sname,student.sdept,sum(sc.grade) from sc
join student on student.sno = sc.sno
where student.sdept = '计算机'
group by student.sname,student.sdept
order by
)

15. delete from sc where grade < 50
16. update sc set grade += 5 from sc
join course on course.cno = sc.cn
join student on student.sno = sc.sno
where student.sno =
(
select student.sno from sc
join course on course.cno = sc.cno
where course.cname = 'c01'
)

17. update sc set grade += 10 from sc
join student on student.sno = sc.sno
where student.sno =
(
select student.sno from student
join sc on sc.sno = student.sno
join course on course.cno = sc.cno
where student.sdept = '计算机' and course.cname = '计算机文化基础'
)

18. create view [A] as
select student.sno,student.sname,student.sdept,course.cno,course.cname,sc.grade from sc
join student on student.sno = sc.sno
join course on course.cno = sc.cno

19. create view [A] as
select student.sno,avg(sc.grade) from sc
join student on student.sno = sc.sno
group by student.sno

20. create view [A] as
select student.sno,sum(sc.grade) from sc
join student on student.sno = sc.sno
group by student.sno

21. create index A on student(sname)
22. 不会

② 使用t-sql语句创建course表,课程表

create table course
(
courseID int primary key,
courseName varchar(30)
)

③ Student(S#,Sname,Sage,Ssex) 学生表 Course(C#,Cname,T#) 课程表 SC(S#,C#,score) Teacher(T#,Tname)

除了sex和age都用string类型的吧，不然会麻烦

④ 教师表A(tno,tname),课程表B(tno,cno,cname),列出每个教师的课程数，SQL语句怎么写啊

⑤ 数据表 学生表，老师表，课程表，成绩表 S（S#,Sname）T(T#,Tname,age)C(C#,Cname,T#) SC(S#,c#,sore)

1. select 学号，avg(成绩复) from 表名 where avg（成绩）>60 group by 学号
2、制update 表名 set 名字=’王文‘ where 课程=‘地理’
3和4 我不写了 我不清楚字段是什么 。这个都应该是操作多张表 你根据他们的关联性去写吧 关联性 有找主外键用主外键作为条件，没有就找关联性 相同的字段，进行修改、删除操作

⑥ 问问经常做T25的小伙们，周五的课程表有两项，是都要做，还是选一项做

当然是都做，后面两个阶段也是都有这样一天两节的。

⑦ 课程表中的G.S.,I.T.,M.I.是什么课

外贸口越家外汇相应百姓家庭首快速增加口东西要外购买花钱买产品相应没更钱投资必须扩内需才能带投资热潮（拉经济增三杠杆——口贸易股市期货扩内需）

⑧ 有四张表 student(s#,sname,sage,sex)学生表，Course(c#,cname,t#)课程表，SC（s#,c#,score）成绩表，

全部通过测试-----
第一题
select a.sno,count(a.sno) as 选课数,Sum(c.score) as 总成绩
from student as a,course as b,SC as c
where a.sno=c.sno and b.cno=c.cno
group by a.sno
第二题
select sno,sname from student
where sno in(
select distinct(d.sno)
from student as d,sc as e
where
d.sno=e.sno and e.sno<>'001' and
e.cno in
(
select b.cno
from student as a,course as b,SC as c
where a.sno=c.sno and b.cno=c.cno and a.sno='001'
))
第三题
update sc
set score=(select e.cavgScore from(
select cno as classno,avg(score) as cavgScore
from sc
where cno in(
select cno
from course as a,teacher as b
where tname='叶平')
group by cno) as e where classno=cno)
第四题
delete from sc
where sc.cno in
(
select a.cno
from course as a,teacher as b
where a.tno=b.tno and b.tname='叶平'
)

⑨ 外国大学的课程表上的这些名词是什么意思 LET ONLY, S/U ONLY；还有TR,MW,M,,F,T等

我也在找答案，不过我知道的比你稍微多一点，LET ONLY意思是只有讲座，TR可能是周四M是周一W周三F周五T周二，但是我们学校选课表上出现了单独的R我弄不清楚了，不过先帮了你吧