八零后课程表
⑴ access里,新建查询查询课程表中学时为80或者课程号以30开头的所有课程信息
摘要所谓管理,是指组织中的管理者,通过实施计划、组织、人员配备、领导、控制等职能来版协调他人的活动,是他人同自权己一起实现既定目标的活动过程。管理学是系统研究管理活动的基本规律和一般方法的科学,它是适应现代社会化大生产的需要产生的,它的目的是:研究在现有的条件下,如何通过合理的组织和配置人、财、物等因素,提高生产力的水平。管理学是一门综合性的交叉学科。管理过程的动态性、复杂性和管理对象的多样性决定了管理所要借助的知识、方法和手段要多样化。
⑵ 在学生表,课程表,成绩表和老师表四个表中,查询课程为'数据库'的,且成绩在70到80之间的学生信息
要有表结构才可以写sql
⑶ 我在跟着keep课程表,80公斤减到74公斤,我下午4点半吃完饭,6点半开始锻炼
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⑷ 在“成绩表”、“学生表”和“课程表”中,找出“课程编号”为“001”的课程成绩在[80,90]之间的学生的姓
“成绩表”、“学生表”和“课程表” 这三个表是什么关系
⑸ 跳皮筋歌谣《小小课程表》90后的,有知道的吗
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3、我是一只小青蛙, 张开嘴巴叫呱呱。 请你不要嫌我吵, 田里害虫归我抓。
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⑹ SQL语句的一道题 三个基本表:学生表(Student)、课程表(Course)、学生选课表(SC)
1. select * from SC
2. select Sname,Sage from Student where Sdept = '计算机'
3. select Sno,Cno,Grade from SC where Grade >= 70 and Grade <= 80
4. select Sname,Sage from Student where Sage between 18 and 20 and Ssex = '男'
5. select top 1 Grade from SC where Cno = 'C01'
6. select max(Sage),min(Sage) from Student
7. select Sdept,sum(Sno) from Student group by Sdept
8. select course.Cname,sum(sc.Sno),max(Grade) from SC
join studet on Student.Sno = SC.Sno
join Course on Course.Cno = SC.Cno
group by course.cname,max(grade)
9. select sum(Cno),avg(Grade) from SC
join Course on Course.Cno = SC.Cno
join Student on Student.Sno= SC.Sno
order by SC.Sno
10. select Stuent.Sno,Stuent.Sname,sum(Grade) A from SC
join Student on Student.Sno = SC.Sno
group by sc.Sno,student.Sname
having A > 200
11. select Student.Sname,Student.Sdept from Student
join Course on Course.Cno = SC.Cno
join SC on SC.Sno = Student.Sno
where SC.Cno = 'C02'
12. select Student.sname,course.cno,sc.grade from sc
join student on student.sno = sc.sno
join course on course.cno = sc.cno
where sc.grade >= 80
order by sc.grade desc
13. select cno,cname from
(
select course.cno,course.cname,sun(sno) from student
join course on course.cno = sc.cno
join sc on sc.sno = student.sno
group by cno,cname
having sun(sno) > 0
)
14. ① select student.sname,student.sdept from
(
select student.sname,student.sdept,course.cname from student
join sc on sc.sno = student.sno
join course on course.cno = sc.cno
where course.cname = 'C01'
)
② select student.sno,student.sname from
(
select student.sno,student.sname,student.sdept,sc.grade from sc
join student on student.sno = sc,sno
where student.sdept = '信息' and sc.grade >= 80
)
③ select top 1 student.sname from
(
select student.sname,student.sdept,sum(sc.grade) from sc
join student on student.sno = sc.sno
where student.sdept = '计算机'
group by student.sname,student.sdept
order by
)
15. delete from sc where grade < 50
16. update sc set grade += 5 from sc
join course on course.cno = sc.cn
join student on student.sno = sc.sno
where student.sno =
(
select student.sno from sc
join course on course.cno = sc.cno
where course.cname = 'c01'
)
17. update sc set grade += 10 from sc
join student on student.sno = sc.sno
where student.sno =
(
select student.sno from student
join sc on sc.sno = student.sno
join course on course.cno = sc.cno
where student.sdept = '计算机' and course.cname = '计算机文化基础'
)
18. create view [A] as
select student.sno,student.sname,student.sdept,course.cno,course.cname,sc.grade from sc
join student on student.sno = sc.sno
join course on course.cno = sc.cno
19. create view [A] as
select student.sno,avg(sc.grade) from sc
join student on student.sno = sc.sno
group by student.sno
20. create view [A] as
select student.sno,sum(sc.grade) from sc
join student on student.sno = sc.sno
group by student.sno
21. create index A on student(sname)
22. 不会
⑺ 林业信息数据库 查询平均分大于80且参考人数大于30人的课程信息,包括课程编号,课程名称字段
select 课程来表.课程编源号,课程名称
from 课程表 join 修课表 on 课程表.课程编号=修课表.课程编号
group by 课程表.课程编号,课程名称
having avg(成绩)>80 and count(*)>30
⑻ SQL Server:学号、姓名、专业在学生表,课程号、成绩在选课表,查询工商管理专业成绩在80分
从表关系上看,应该有学号字段的主外键关系
学生表: 学号,姓名,专业
选课表:回学号,课程号,成绩答
select 姓名,学号,课程号,成绩 from 学生表 A
left join 课程表 B ON A.学号=B.学号
where 1=1
and A.专业=‘工商管理’
and B。成绩〉=80
⑼ 查询平均分大于80且参考人数大于30人的课程信息,包括课程编号、课程名称字段
select 课程表.课程编号,课程名称
from 课程表 join 修课表 on 课程表.课程编号内容=修课表.课程编号
group by 课程表.课程编号,课程名称
having avg(成绩)>80 and count(*)>30