课程表综合成绩怎么算

⑴ 已知三个关系模式(学生表,课程表,成绩表)用SQL语句实现以下内容

CREATE TABLE 选课表

(学号 CHAR(8) REFERENCES 学生表(学号),
课程编号 CHAR(6) REFERENCES 课程表(课程编号),
成绩 smallint)
GO
INSERT INTO 学生表 VALUES('20100101','李丹','女','1993-6-6','管理系')

GO
SELECT 学号,姓名,所在系

FROM 学生表
GO
SELECT 学生表.学号,姓名
FROM 学生表 JOIN 选课表 ON 学生表.学号=选课表.学号
WHERE 课程编号='A01-02'
GO
SELECT *
FROM 学生表
WHERE 姓名 LIKE '[赵李张]%'
GO
SELECT 课程名称,COUNT(*) AS 选修总人数

INTO 修课统计
FROM 课程表 JOIN 选课表 ON 课程表.课程编号=选课表.课程编号
GROUP BY 课程名称

⑵ 求sql语句 有一张课程表（course）和一张成绩表(score)

select sc_name from [成绩表内容] where sc_number like '14%' and sc_sex = 0;

select a,co_name , b.sc_name b. sc_score from [课程表] a , [成绩表] b where a.co_id =sc_courseid and b.sc_score < 60

select sc_name , sum(sc_score) / count(sc_score) range from [成绩表] group by sc_name

order by range

⑶ 如何查询成绩以及查看课表

查看云南省昭通市镇雄县塘房镇塘中吉茂骞初二考试成绩

⑷ 根据学生表，课程表和成绩表，查询学生的学号，姓名，课程号，课程名和分数。（多表查询

直接将三表关联查询就可以了 select b.姓名,c.课程,a.成绩 from 成绩专表 a,学生表属 b,课程表 c where a.学生学号 = b.学号 and a.课程编号 = c.编号 and a.成绩 < 60

⑸ SQL查询，学生表，课程表，成绩表的一个查询要求如下怎么写呢

selects.sid,s.sname,sc.scorefromstudent,course,scwherestudent.sid=sc.sidandcourse.cid=sc.cidandcourse.cname='影视设计';

注意一下，你自己写的sid和sname中间没有逗号，到时候一定执行报错

⑹ SQL语句的一道题 三个基本表：学生表(Student)、课程表（Course）、学生选课表（SC）

1. select * from SC
2. select Sname，Sage from Student where Sdept = '计算机'
3. select Sno,Cno,Grade from SC where Grade >= 70 and Grade <= 80
4. select Sname,Sage from Student where Sage between 18 and 20 and Ssex = '男'
5. select top 1 Grade from SC where Cno = 'C01'
6. select max(Sage),min(Sage) from Student
7. select Sdept,sum(Sno) from Student group by Sdept
8. select course.Cname,sum(sc.Sno),max(Grade) from SC
join studet on Student.Sno = SC.Sno
join Course on Course.Cno = SC.Cno
group by course.cname,max(grade)

9. select sum(Cno),avg(Grade) from SC
join Course on Course.Cno = SC.Cno
join Student on Student.Sno= SC.Sno
order by SC.Sno

10. select Stuent.Sno，Stuent.Sname，sum(Grade) A from SC
join Student on Student.Sno = SC.Sno
group by sc.Sno,student.Sname
having A > 200

11. select Student.Sname,Student.Sdept from Student
join Course on Course.Cno = SC.Cno
join SC on SC.Sno = Student.Sno
where SC.Cno = 'C02'

12. select Student.sname,course.cno,sc.grade from sc
join student on student.sno = sc.sno
join course on course.cno = sc.cno
where sc.grade >= 80
order by sc.grade desc

13. select cno,cname from
(
select course.cno,course.cname,sun(sno) from student
join course on course.cno = sc.cno
join sc on sc.sno = student.sno
group by cno,cname
having sun(sno) > 0
)

14. ① select student.sname,student.sdept from
(
select student.sname,student.sdept,course.cname from student
join sc on sc.sno = student.sno
join course on course.cno = sc.cno
where course.cname = 'C01'
)

② select student.sno,student.sname from
(
select student.sno,student.sname,student.sdept,sc.grade from sc
join student on student.sno = sc,sno
where student.sdept = '信息' and sc.grade >= 80
)

③ select top 1 student.sname from
(
select student.sname,student.sdept,sum(sc.grade) from sc
join student on student.sno = sc.sno
where student.sdept = '计算机'
group by student.sname,student.sdept
order by
)

15. delete from sc where grade < 50
16. update sc set grade += 5 from sc
join course on course.cno = sc.cn
join student on student.sno = sc.sno
where student.sno =
(
select student.sno from sc
join course on course.cno = sc.cno
where course.cname = 'c01'
)

17. update sc set grade += 10 from sc
join student on student.sno = sc.sno
where student.sno =
(
select student.sno from student
join sc on sc.sno = student.sno
join course on course.cno = sc.cno
where student.sdept = '计算机' and course.cname = '计算机文化基础'
)

18. create view [A] as
select student.sno,student.sname,student.sdept,course.cno,course.cname,sc.grade from sc
join student on student.sno = sc.sno
join course on course.cno = sc.cno

19. create view [A] as
select student.sno,avg(sc.grade) from sc
join student on student.sno = sc.sno
group by student.sno

20. create view [A] as
select student.sno,sum(sc.grade) from sc
join student on student.sno = sc.sno
group by student.sno

21. create index A on student(sname)
22. 不会

⑺ 用SQL对学生表、课程表、成绩表进行多表查询。

CREATE TABLE 选课表

(学号 CHAR(8) REFERENCES 学生表内(学号),
课程编号 CHAR(6) REFERENCES 课程表(课程编号),
成绩 smallint)
GO
INSERT INTO 学生表 VALUES('20100101','李丹','女','1993-6-6','管理系容')

GO
SELECT 学号,姓名,所在系

FROM 学生表
GO
SELECT 学生表.学号,姓名
FROM 学生表 JOIN 选课表 ON 学生表.学号=选课表.学号
WHERE 课程编号='A01-02'
GO
SELECT *
FROM 学生表
WHERE 姓名 LIKE '[赵李张]%'
GO
SELECT 课程名称,COUNT(*) AS 选修总人数

INTO 修课统计
FROM 课程表 JOIN 选课表 ON 课程表.课程编号=选课表.课程编号
GROUP BY 课程名称

⑻ 在学生表，课程表，成绩表和老师表四个表中，查询课程为'数据库'的，且成绩在70到80之间的学生信息

要有表结构才可以写sql

⑼ 超级课程表查的成绩是综合成绩还是原始成绩

综合成绩，你的学校教务系统显示分数是多少就是多少

⑽ 写一个sql;比如有课程表，学员表，分数表；查询出每个课程的前三名同学；考虑优化问题；大神答出追加100分

fra_id是分抄数吧
select * from 分数表袭 a ( join 课程表 b on a.obj_id=b.obj_id）join 学员表 c on a.s_id=c.s_id
where a.s_id in (select top 3 fra_id from 分数表 group by obj_id,s_id) group by b.obj_id,c.s_id

不知道对不